그렇게 많은 IT인증덤프공부자료를 제공하는 사이트중ITExamDump의 인지도가 제일 높은 원인은 무엇일가요?그건ITExamDump의 제품이 가장 좋다는 것을 의미합니다. ITExamDump에서 제공해드리는 Microsoft인증 70-457덤프공부자료는Microsoft인증 70-457실제시험문제에 초점을 맞추어 시험커버율이 거의 100%입니다. 이 덤프만 공부하시면Microsoft인증 70-457시험패스에 자신을 느끼게 됩니다.
ITExamDump의 제품들은 모두 우리만의 거대한IT업계엘리트들로 이루어진 그룹 즉 관련업계예서 권위가 있는 전문가들이 자기만의 지식과 지금까지의 경험으로 최고의 IT인증관련자료를 만들어냅니다. ITExamDump의 문제와 답은 정확도 적중률이 아주 높습니다. 우리의 덤프로 완벽한Microsoft인증70-457시험대비를 하시면 되겠습니다. 이렇게 어려운 시험은 우리Microsoft인증70-457덤프로 여러분의 고민과 꿈을 한방에 해결해드립니다.
Microsoft인증 70-457시험을 패스하여 자격증을 취득하는게 꿈이라구요? ITExamDump에서 고객님의Microsoft인증 70-457시험패스꿈을 이루어지게 지켜드립니다. ITExamDump의 Microsoft인증 70-457덤프는 가장 최신시험에 대비하여 만들어진 공부자료로서 시험패스는 한방에 끝내줍니다.
ITExamDump는 여러분이 원하는 최신 최고버전의 Microsoft 인증70-457덤프를 제공합니다. Microsoft 인증70-457덤프는 IT업계전문가들이 끊임없는 노력과 지금까지의 경험으로 연구하여 만들어낸 제일 정확한 시험문제와 답들로 만들어졌습니다. ITExamDump의 문제집으로 여러분은 충분히 안전이 시험을 패스하실 수 있습니다. 우리 ITExamDump 의 문제집들은 모두 100%합격율을 자랑하며 ITExamDump의 제품을 구매하였다면 Microsoft 인증70-457시험패스와 자격증 취득은 근심하지 않으셔도 됩니다. 여러분은 IT업계에서 또 한층 업그레이드 될것입니다.
우리ITExamDump 에서 제공하는 학습가이드에는 IT전문가들이 만들어낸 시험대비 자료들과Microsoft 70-457인증시험의 완벽한 문제와 답들입니다. 그리고 우리ITExamDump에서는 IT업계에서의 높은 신뢰감으로 여러분들한테 100%보장을 드립니다. 우리에 믿음을 드리기 위하여Microsoft 70-457관련자료의 일부분 문제와 답 등 샘플을 무료로 다운받아 체험해볼수 있게 제공합니다.
IT인증시험에 도전해보려는 분들은 회사에 다니는 분들이 대부분입니다. 승진을 위해서나 연봉협상을 위해서나 자격증 취득은 지금시대의 필수입니다. ITExamDump의Microsoft인증 70-457덤프는 회사다니느라 바쁜 나날을 보내고 있는 분들을 위해 준비한 시험준비공부자료입니다. ITExamDump의Microsoft인증 70-457덤프를 구매하여 pdf버전을 공부하고 소프트웨어버전으로 시험환경을 익혀 시험보는게 두렵지 않게 해드립니다. 문제가 적고 가격이 저렴해 누구나 부담없이 애용 가능합니다. ITExamDump의Microsoft인증 70-457덤프를 데려가 주시면 기적을 안겨드릴게요.
시험 번호/코드: 70-457
시험 이름: Microsoft (Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1)
당신이 구입하기 전에 시도
일년동안 무료 업데이트
100% 환불보장약속
100% 합격율 보장
Q&A: 172 문항
업데이트: 2014-02-11
70-457 덤프무료샘플다운로드하기: http://www.itexamdump.com/70-457.html
NO.1 You are developing a database application by using Microsoft SQL Server 2012. An application that
uses a database begins to run slowly. Your investigation shows the root cause is a query against a
read-only table that has a clustered index.
The query returns the following six columns:
. One column in its WHERE clause contained in a non-clustered index
. Four additional columns
. One COUNT (*) column based on a grouping of the four additional columns
You need to optimize the statement. What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: F
Microsoft 70-457최신덤프 70-457인증 70-457기출문제 70-457 dumps 70-457
NO.2 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the top half of the students arranged by their average marks must be given a rank of 1 and the
remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D
Microsoft 70-457시험문제 70-457 dump 70-457자료 70-457 pdf
NO.3 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, incremental ranks must be given based on the order
they are created.
. Ranks must be sequential without gaps in between.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: C
Microsoft 70-457 70-457인증 70-457자격증 70-457
NO.4 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, the same rank must be given to these students.
. Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use.?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A
Microsoft 70-457 70-457 70-457 70-457덤프
NO.5 You are developing a database application by using Microsoft SQL Server 2012. You have a query that
runs slower than expected. You need to capture execution plans that will include detailed information on
missing indexes recommended by the query optimizer.
What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: K
Microsoft dump 70-457 70-457기출문제
ITexamdump의 642-980덤프의 VCE테스트프로그램과 646-048덤프는 한방에 시험을 패스하도록 도와드립니다. ITexamdump 에서는 최신버전의 74-343시험에 대비한 고품질 덤프와 CD0-001시험 최신버전덤프를 제공해드립니다. 최고품질 JK0-U11시험자료는 100% 간단하게 시험패스하도록 최선을 다하고 있습니다. IT인증시험패스는 이토록 간단합니다.
댓글 없음:
댓글 쓰기